#SDNU1683. easy problem Ⅳ

    ID: 427 Type: Default 1000ms 32MiB Tried: 0 Accepted: 0 Difficulty: (None) Uploaded By: Tags>Fibonacci数列欧几里得算法

easy problem Ⅳ

Description

定义斐波那契数列,F(1)=F(2)=1F(1) = F(2) = 1,对于所有的NN,满足F(N+2)=F(N+1)+F(N)F(N+2)=F(N+1)+F(N),求F(m)F(m)F(n)F(n)的最大公约数 多组测试用例

Format

Input

多组输入,每组两个整数n,mn,m,(1n,m1000)(1\le n,m\le 1000)

Output

F(m)F(m)F(n)F(n)的最大公约数,保证结果不超过26312^{63}-1

Samples

1 2
1